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WAEC 2026/2027 Further Maths OBJ/ESSAY Questions and Answers

2026/2027 WAEC May/June Further Maths (OBJ) Objectives and (ESSAY) Theory Questions and Answers EXPO Room for School Candidates & private|WAEC Furthe

Complete 2026/2027 WAEC May/June Further Maths (OBJ) Objectives  and (ESSAY) Theory Questions and Answers EXPO Room for School Candidates & private|WAEC Further Mathematics (OBJ/ESSAY) Questions and Answers. 2026 WAEC FREE QUESTION AND ANSWER ROOM FOR Further Mathematics OBJ THEORY [School Candidates


WAEC 2026/2027 Further Maths OBJ/ESSAY Questions and Answers

2026 WAEC Further Maths (OBJ) Objectives Answers:

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2026 WAEC Further Mathematics (ESSAY) Theory Answers:


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Sample Past WAEC 2023 Further Mathematics Questions & Answers

1. Arithmetic Progression Problem

Given:

  • First term: -8

  • Last term: 52

  • Sum: 286

Solution:

  1. Number of terms:

S=n2(a1+an)    286=n2(8+52)    13 termsS = \frac{n}{2} (a_1 + a_n) \implies 286 = \frac{n}{2}(-8+52) \implies 13 \text{ terms}
  1. Common difference:

an=a1+(n1)d    52=8+12d    d=5a_n = a_1 + (n-1)d \implies 52 = -8 + 12d \implies d = 5

2. Probability Question

Given:

  • P(n) = 1/3, P(n’) = 2/3

  • P(T) = 1/5, P(T’) = 4/5

Solution: Probability that only one solves it:

(1/3×4/5)+(1/5×2/3)=2/5(1/3 \times 4/5) + (1/5 \times 2/3) = 2/5

3. Vector Calculation

Given:

  • m = 3i - 2j

  • n = 2i + 3j

  • p = i + 6j

Expression:

4m+2n3p4m + 2n - 3p

Solution:

4(3i2j)+2(2i+3j)3(i+6j)=19i20j4(3i-2j) + 2(2i+3j) - 3(i+6j) = 19i - 20j

4. Matrix Equation Problem

Equation:

(x3)[4326x]+4[...]+3[...]=24(x-3) \begin{bmatrix}-4 & 3 \\ 2 & 6-x\end{bmatrix} + 4[...] + 3[...] = -24

Solution: After simplifying and factoring:

x=1 or x=2x = 1 \text{ or } x = 2

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